QCM corrigé nombres complexes 0 analyse numérique, arithmétique, corrigé, denombrement, géométrie analytique, mathematique, nombres complexes, probabilité, QCM, series, suites 09 h 14 QCM nombres complexes corrigé math analyse numérique licence QCM Nombres complexes Q u e s t i o n 1 Le nombre complexe 1 + i 3 1 − i 20 v a u t : □ 2 9 □ i 2 9 □ 2 9 1 + i 3 ☑ 2 9 1 − i 3 Q u e s t i o n 2 Soit u racine 5 i è me de l ' u n i t é et u ≠ 1 , alors 1 + u + u 2 + u 3 est é gale : □ 1 u ☑ − 1 u □ 1 u − 1 □ 1 u + 1 Q u e s t i o n 3 ∑ k = 1 10 sin 2 k π 7 + icos 2 k π 7 est é g a l e : □ 1 □ − 1 □ i ☑ − i Q u e s t i o n 4 le module du nombre complexe Z = 2 + i 5 2 − i 5 10 + 2 − i 5 2 + i 5 10 v a u t : ☑ 2 c o s 20 arcos 2 3 □ 2 s i n 20 arcos 2 3 □ 2 c o s 10 arcos 2 3 □ 20 cos 2 arcos 2 3 Q u e s t i o n 5 la partie r é elle du nombre comple ω = 1 − cos θ + 2 i s i n θ − 1 est é g a l e : □ 1 3 + 5 c o s θ ☑ 1 5 + 3 c o s θ □ 1 3 − 5 c o s θ □ 1 5 − 3 c o s θ Q u e s t i o n 6 Soit ω le point d ' a f f i x e i . L ' e x p r e s s i o n complexe du rotation de centre ω et d ' a n g l e π 2 est ☑ z ' = iz + 1 + i □ z ' = − iz + 1 + i □ z ' = iz − 1 + i □ z ' = iz + 1 − i Q u e s t i o n 7 On considere le nombre complexe ω = 2 3 e 2 i π 3 , on pose α n = ω n + 1 − ω n Alors on a : ☑ α n = 19 3 2 3 n □ α n = 2 3 n + 1 − 2 3 n □ α n = 15 13 2 3 n □ α n = 13 15 2 3 n □ α n = 3 19 2 3 n Question 8 Soit I le po int d ' affixe 3 i . L ' ensemble des po int s d ' affixes z telque iz + 3 z − 3 i = 1 est : □ l ' axe des abscisse . □ l ' axe des ordonn é es priv é du po int I . □ une cercle de rayon 1 priv é e du po int I . ☑ le plan priv é du po int I . Question 9 On pose S = 1 + 2 ω 0 + 3 ω 2 0 + ... + n ω 0 n − 1 avec ω 0 est la racine ni è me de l ' unit é . S vaut alors : □ S = 1 ω 0 − n □ S = n ω 0 − n □ S = 1 ω 0 − 1 ☑ S = n ω 0 − 1 Question 10 − 1 + − 3 2 3 n + − 1 − − 3 2 3 n vaut : □ − 1 □ 1 ☑ 2 □ 3 MMF.7h_3?`00kEY]Lm|f4_h5oPojIVZ6dA00Go==E]GDLkJD|mBdLoEmH2C6ahU(^YBDf|kX_al00^B212QI]Zo^CN)aPmg5bnj3gLD2d_Gii(OYeNE`OSjMW7`o^AiMSHOcjIEe6FonLaWOY8_Nab;_oI9V_Fo18)ROG(o?iaMSjd^n;BSaJG`eX`(]cnkiM|nQW1n6lk55fhSnHPMAPH?OHoNmPjQ`o)_7Rn7ia)ZOk4j^In?io7cbPBdjVdf6Uf?[agRabH^7gRcIK=;|QPiHKbc7?R_RiBYij?dDIl_NnGaD;TA5b;jl72GIIU|lC98o:SJfco;lJfnHKM;O]g759WG_jF[iXDRB[iG(kI1inUEl?C_*;akJ8hYHVQ*mf3VbinU]|VJlgUEn6fNeJHin7VB`6F43_l]Ze6Df(]R=38HSPnE8KcXbfhh=]V?COQ]|aeffhbkK|FO*`60k;VfWA_CXG;gIiV6Ee48m0=P(077dba0304*;`2(=7F`SE;JASNa*l2WGm_fbCFPKnEi9^:aCF;Hm9|12h5(R4)f0]SdaDlQ72b82Be3oAGHin|iRKBCJ2;*aj(?dl0IQBKQ0`?*8gK;]0gi0SG(6A50QYd*gYPQba7Y)YNhMRaiTbcIVj8PfFmfG6[;EPh6Tf?ZbkL)96*j8B8XQhD|RDWC33QR6P*ZH0A19PT1TG4QhH0QD0*NeKSQDeh*H4;hIF10804;h5TR2E1]82KP7a5(V9gjm;PV0hBB4LdN0L246;WM6(H6;PJT^PMeLB9*Z^;8SDn5M9AC)8=dW18Jh4G*Vj8XNE(=SJXSa7]`:cfEn8]g1hf4Q[O9lj0(Ndd:Pk8FP7MFNiS^PSFXHO*cJ40BO;bl9[ikEml5(K1)8e((?^LFBRV[_2F0`1=0A0[1n`=HWX^ebI0=1NG08(ej^6*1G3=Sj8Q*3kXM2iI0]ClAL8E`n;?e*DPB:X2)6YAM8bZm=2iT2kjYd4099E:|F)J0=8S72H(F8e(Q6;W3_b0(K4oU`B00l9PXQ4H48*hjSi1H7ZBAF4QL1VLMa8N7E6h*L9BTiPD:542kT04M4b55TBVY4?35E8|:Q[HAUF5JT1`OjT0Q|]bHH:)nZ:AEDN8:|MQoa58TUPB718d(B41:N8g55`Ke1?4f65*EL0f4*78RWbHY0((4P0^83dDCYe1eMT5bAb9ANeEGI7Ih|:b1i]ZbY2Y8?`hodb7A|[[I=j?lUEJk9Y8QCZYCn22Wg8Rj7ob(Q9GAD:?RQn1_bc(NT;YfA20VgT]=4B3g)JOd8ZLne(6TEE=:0B`=56WJ)SK[Af0(FHU_BnV5hG4fWLl|Id7Qb1SkmAJa1WHbbn;U`nlEBBk6BQc*lg2hWB`7AM=KDWZF0eMc3X|Q5?eI^WZEIG3bDM43YBG8CKi:B3RUmUJcRCIYW9BNRW4maTLJOE`TFfS8CaY^5X9Sbho]=4*|JPa53`B)0MbIh;^2=1(l3_1l4cmL15^RHX*T55)T0MTcMnKd0X(K_0a0fOQ60^?7RG`D)NfgTN;UO8HL35CTL]Y73DA|iG|dgT))EO0)iAQD_V3[g8DKo8Ij^^fo|7ZS8TK2178TJb;U)2cTG]I5c(DC)9BYb[]]6c_GJb;Un6cTgJ20G[fSD|:A)ceIJH=0BRMF=9N7H[)idF8?b2K_ba8GBWC1fV*lLgU]bGEK0S2j^J0:Hi(E]_)[=To^=b8TRP`c:;(9j|F?Uj|?I^k?E=Q5YUjgY4*mfW5i(Va?BE(?oJAYdF3E8VEoK5Hhin`OGW;IV?emJ;7^OCnHFDf7fdoBG|n5|c8*k=_UT?Yk(fA_(9C]cn]n_ckiOSgjcKM^gfCnfk[n]Ohh^nmLcV_okKMTT_oeL96^SO97OgZfBnj[7C[o2=UTcUd8])AEN99[I:CoSBn]ULUTYYGVN7V?L_;WU=na4kP3cDHQfojfLX^;Q2?DeGM)6YYecT23Dcd6E*JR5Ncf);_:Y)IWCgfVhV70f7D;o^7*LWCUXkBO[b(O[(?|FKcO_Bk=Vm=KRj975ON?D4Ieigo3dVN?g38LK[D[I_S*fXW(CjPd*R5O*2QGmb7d=5EEoNhj:aRS3^RRKiNU6KlmFcbkRAIXI`|nS:VmED0Q^M[Xe35hJn:_CKLIdK4i(m=fC3W?XZN`fnNSJePn8EgVQBg0MC[DelheabL?bRH)8:IKYAT^==G2YOFoRU*5aGCKXB9mKLdhdIZaV:8T0N8eE3SGRh3)PNE[m3c*aW2A7JV;(4:BLKlhZ*6gFFJOIWT)EM`]dV*Io;J?3iiV[NG1Y1_3n:0cJdJOYC6oK^n|;FU2bX||*DNTRGknBnRlBSO]?HJCYXCdkM1fKYh|a2[DMSDkSj]0bYIKKO;TebIJ64nLY1IlZoEOU*HLEP_PYQN2N8|hc5W47;ge|oFQNn_Sj4CWPX3XNcILgjDoLb6NS^JlJij7IB4?=7=HZloG5C75PkR?Jg6M8fJgRf5bo=dn)_hSJgFRS]jZfPKo7Moi4HhbWBo_YP9d^|EkE^kSHY8JcX3SP44iF;glfeFL[L*?MNGCHII3_`LabOLM`al0Y3k6bRb49VDZ5eb]O)Xh7L_Sah9GF=g^GUSkgj]6QXWNhR^C5EC`NAL=9mo8X7ZJR3TF3RRn=XS6]n?_N*VBhjQhT3?5nUjNIhO5QNAYonI:Jb]AdX7go?4g^khYT_FI_kTLD_jJDENBKlQgoBJl`RbCK5:eTmXCg5`Y1M[=:)_`53d9K7QW(_NB^B[jhNcGIK;)=nF_OXmgSZN6BVChJlZci*G7OZEb]IN]^FJnhWWh]kE7`BV^Ik3[R^ZVmW4n=4I:]dfER)Z5=TObD6fOcG(Nn;99PiLo(*0=R=n|Tb(O*^b|Vjlfk1SK8L8UlZFT|4PdR[5^Th|_WF(Q;jiAKSeN2[Ai)n6?mb6:_YRX`YXabUjl1F1h72FT;b:blHSH;986`jBjE6Af(clIMK)lD)ejBH]`_onkdWe[A[T?cZk0904)anUjCW9j2CdM987bSLJ^5OE3d]5_]PEOniQD0G(S=efG1MZRjXZ9Y|[Z^dYWfdj)S7)f]6KKO[mn`l|oMUMYi^cji=IZ6](lfZVg*kon6|YW^E93oQ_89D4HVdokoT9*WBk=(jkLTXM1BoLSI)ZnKX1bSE*?k2bmDeY;m)FEo6YLYY_b8EC4SBmjT[8^ZLi:]Tm_?L)hUn)8:G6QT[Lf[0M5SgM`TZmngnkm^0_5ok;`)Zo_Ji|7bF)7[YZe?Sd)MD2V1A3g?BgEQ;gPC6VTo9jJkF0=gK`8mo[aNY6]F5eIKM|*|NK7((nYYFo4RIBWkFZCO:U4eO=_YHNMVOKKP)`od(U`|E8NZfdGl00Y1R9fR4EGfB;GPGEH=VEFL_IcmQ`Nfc7K`5ZIDoCCTnjXg2LoTCliEJBh3aX8O=O7PKYO_iOLVc8(6P`5H9S(_0nO(jR]YFFEE_N|GDR_nUR`JMknf6[YX0HoFcBoAF5UJKQFkWL4_b2RNEHN4n4:(m:*ZjLgZc^ac911_iJg55;;emUAYZie;g?HQfCR^MXLV]|b*a9k`g_QfU(kN|];XB:BE9?=FU)i6n_24QAai*nhh[Sg`:P(=[_R:jY8;_`HZNN8SlkYd?70^iIbFC?F:kX5GXV=Z^[9bb^ZL9E;V0NG(bn4SK[9o2GaTH]EWDWQjJ88OJHm`[)eKe_C:kniTMo9OEXFKM`.mmf TELECHARGER VERSION PDF QCM corrigé nombres complexes QCM nombres complexes corrigé math analyse numérique licence QCM ... 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QCM corrigé Analyse numérique licence master 0 analyse numérique, arithmétique, continuité, denombrement, dénombrement, mathematique, nombres complexes, probabilité, QCM licence math, QCM Master math, series, suites 06 h 58 QCM Analyse numérique licence master Q u e s t i o n 1 On désigne par x la partie entière de x . lim x → 1 x 2 − 1 x 2 − 1 = □ 2 □ 0 □ 1 □ n ' e x i s t e pas Question 2 On considére la suite x n pour tout n ∊ ℕ définie par ; x n = x n − 1 + x n − 2 + .... + x 0 , ∀ n ∊ ℕ Quelle est la nature de x n ? □ x n est une suite géomtrique □ x n est une suite arithmétique □ x n est une suite constante □ On ne peut pas en conclure Question 3 L ' e q u a t i o n x 2 − 2 2 − 5 2 = 1 admet dans ℝ : □ 4 solutions □ 5 solutions □ 6 solutions □ 7 solutions □ 8 solutions Question 4 Soit f d é rivable en a , lim h → 0 f 2 a + 3 h − f 2 a − h h = □ 8 f a f ′ a □ 8 f 2 a f ′ a □ 4 f a f ′ a □ 2 f a f ′ a Question 5 On pose f x = 1 x 2 ∫ 3 x 2 u − 3 f ′ u du . f ′ 3 = □ 1 / 2 □ 3 / 2 □ 1 / 4 □ − 1 / 3 Question 6 Siut u n la suite réelle définit par 1 − u n u n + 1 > 1 / 4 et 0 ≤ u n ≤ 1 ∀ n ∊ ℕ , lim u n = n → + ∞ □ 0 □ 1 / 2 □ 1 □ + ∞ □ Aucune de ces réponses Question 7 Pour quelle valeur de α la série dont le terme générale est − 1 n − 1 n + n α converge pour n ≥ 2 ? □ α ≥ 3 / 2 □ α ≤ 2 / 3 □ α ≤ 1 / 2 □ α > 2 / 3 □ α > 3 / 2 Question 8 Soit l ' a p p l i c a t i o n f dans ℂ définie par f ( z ) = z + i z − i pour tout z different de i et on considére E = z ∊ ℂ , ∣ z ∣ = 1 et i ℝ = z ∊ ℂ , Rel z = 0 □ f réalise une bijection de ℂ ∖ i dans ℂ . □ f i ℝ = ℝ □ f i ℝ = E □ f E = i ℝ □ Aucune réponses n ' e s t c o r r e c t e . Question 9 On désigne P E l ' e n s e m b l e des parties de E . Soit E une ensemble de cardinal fini n . le nombre de couples A , B ∊ P E × P E tel que A ⊂ B v a u t : □ 2 n □ 3 n − 1 □ 3 n □ 2 n 2 □ n 2 n − 1 Question 10 Une urne contient 2 boules blanches et n − 2 boules r o u g e s . On effectue des tirages successifs sans remise d ' u n e boule et on note X le rang pour lequel la boule blanche apparait pour la premiere f o i s . E X = □ n + 1 2 □ 2 n + 1 2 □ 3 n + 1 2 □ n + 1 3 Question 11 Soit S l ' ensemble des entiers x tel que x 2 − x + 1 est divisible par 7 . S est alors : □ S = 7 k + 2 , 7 k + 5 , k ∊ ℤ □ S = 7 k + 1 , 7 k + 5 , k ∊ ℤ □ S = 7 k + 3 , 7 k + 5 , k ∊ ℤ □ S = 7 k + 2 , 7 k + 3 , k ∊ ℤ Question 12 lim n → + ∞ ∑ k = 0 n sin 1 n + k = □ 0 □ sin 1 □ ln 2 □ 1 □ + ∞ Question 13 Soit une fonction f d é rivable en x 0 = 0 d é finie de ℝ → ℝ tel que f 0 = 0 et f '( 0 ) = 1 ∀ n ∊ ℕ * lim x → 0 f x × f 2 x × f 3 x × ..... × f n − 1 x x n − 1 = □ n n − 1 / 2 □ n ! □ n n + 1 / 2 □ n − 1 ! □ + ∞ MMF.7h^7D000cA_KL]^hm*_l3niCZ8jR402_jL))k5ECCf(k]KCIC5MmH6CJHB=CGTY:|lWhOn^o:022i068*hTN)gFbl*8h^9`KcPgdo)C|[nLGYn?IbOWI`ON3nO75I3`k_g1)TlfWdn*jFabn:eJ7_fKihIMXi=;1`Gaf(W|kLBJoKi==]|YO(SkdOW8aiN|MOgPH30mM?_;cN3IaX^4Q9ObOBcR0N:m9m9XA3YalN?MfO7;V30k^3^KCbFafL_I6W3fMWXe?9lh_jk*hW:JKCIIOlmW[SN()Cdn?dgbc;OhhBomCW|27RGfH6|)d76K=l?WblTfAYYm[V6N3ZNelHc]B3POf`l?Q;;]9ehMlk?1RMI?T=B*J7ZnfALIYPo=SM3k1Z4K89PSMY8]`dTDi*DPW2)d49ikHZBLhnM*TGae)(JTSi=(^lVTGnA*QWb;TDialJRNOh^*cA?X(8InIi(_aKocZd25QII|(bM1Ghgadb?bbcGRKN:[SlDjX9_T2*1DP403E3|5)TIPDZ4k()i5ZL`DV`g;e[B?JK]TDJ13EYV2:*((OAFG7Zo6kUFS4ZRf`8:XML][LDCD[TSfZe|OP48V8GgD8`8*:kZRf)=iSZR)i(58k4h50e*kPaX8?Q5Dm`HVPj|*JL]B5A0(DZ)10G7DHX8ij|))39A056SJhdDPo4o:0***H0*aQDPIEQmD2i1d?B|OG=VM1Lbh;0N4|PW_7X)=153b1*Z*fl2PPeF=`VPLk9*YN=E6Pl;86:VfXm2L2Q7Pa8(Ag`F4nA((GJ:Se?QB5k`TmZMC1UmNRX|X?X0kh0P^ZfQ5XahfV1BiX0eD8J(?B038QT(MG7KoI=*S0CT88[(8SR2C5EBm^CPWQI*RQ8XCPo52L[bi3j4W)QZ[W`bF2n)[(4:QR:(kgE5_ZXD8i4|Lc]EL4Shm:?Jaj38:P8TJU5UBmX24]4PRl[)e1121aPe[|PSIPOdc1RC5[)1]k*;eS7nQ57(0U8HA4|1)36dILEk(];]6kE3=L35PNeh(M_a4*LCFSi8IJ;h;|8Ri*A49L3JJIAT:1eBGB)[j|;AdY[fGMmN7207K2XMMd15=NeU]ZG946|YHnTBJBEQd:)`cJKlPBJB=YgH)b8M9(AWD_PW^0bd4Hm5?BC=H6QS1`?`PgU6hcDNYWQJ6bU7hmEI))=9He8jFeK7XeBmj(gg6Gj*hUfT?6oeofbS(5U(RN3^Eo5EAZTHC3oa(5IGaEY(HSmC)BUTm0?KhSDa19YN`c1OGUB)^_PPHB2`b[|8J64QYZd:QcKMc=SAg(8T8TEZ`_c|mWSS_RmlTM1O`O4*f^I7a8nXFK:b?m:(N8IHbfPlTB`2bC;I5W2A1AikPXEVZN23J?|S`YoRSk8NnOYMO99Rgk4NmOY4^IS9DS(AmiWaAIlW6IDXF]866bFJRN*7kbME(TZTo1R[4JHf3|B8eiH)aHSOUPk6Le5]PH5]X68h`;9;Haf(FVbj`0L4eV0i1](Pf0O9)Q_lhhj[Li9h?mVW(de3U7XcKWJ=cVW8cV3Lk9B=kPW175Zd6KnS1DOiQ_VajPdd)MLb`b)(MRPg)Nfn:LAmZLlbSTW(MdcWUNVg)NgnJL5k*iihD6ii8U_cDRM)D:4|Won1CEhFeG]VF?2C)F5=YdC`a;Nb06?3GC4i_`bLM_;kP1)5|E=lWbL9IngBRKF?hU8eMJEC5;^9F;=dL_SiKKE9UMMaSh?_?Qa?)ginJ6g=C8?iH6GeH_d_JgCXE[S_h^(NN]jBnWSY39bMW(4BQ(ogKnjm5h)Q70)k7ifFab=Q(5V5?QL`KOidOOilNo3HOLQ8Xoh]ao)OoHYV|QL3:h(n0LN9h?iU?^6`K6n)Gm)[_)Dc_`=RTZ`4cTZJf3nIb_o;CgH|Ik9n1=fcK;1=enTb57lh^*oKM0P9O8n=MABOZ(FaLK[|_|a^2=bh)_TX[im;MbFSGT^FC*W|RIFa5I(BH`SW:i5EIkLW66;BRAD2XgZ|kT1Uh)a]ZIJYADE;E5d9c5YE1_a^BHT8Ta92CdN3RmicIKR9`kRK14LL[C:=ND2^f0^Ad`dP7;GjAO|oD6eM]ej`kXMlBb[Ya0nebNaBYOIiOgV9YRN[oNIQSVYLjH6UFB;8ASd;WJ5_Im=Z_]aPhAY?2d]98YHaGP33(*EeV)gE9P87C0Gfa|g4ELZDQm5_4U^WYFRR(fHf7d29]AM;(Aoc?XOHkK691SIchD6i2hSi*|S)EJ_EaRQWB=:0:VWGW2*i2nQ[NGf_kDLK5gjTPO4[NHHn^hPMOgZi]=TOfnCIlcUSbdfWbj^MllMcb5QM`TnJH;BLbjXU59R]TfHONAJ095Kk4Df_i0Kl5|]o7]Re*m_EG[FR5DAcAUllm3H8S|9X[kHRI2((o^h7M|h?OJ`6:T2J:UUcLY8Z[;9=MUeIRh2o^:eadZi26:^EY^QAcF7D_mQbl=NRee`XNO5)fe];onNVZQ(eeUSJ2LZjIi)IQ_NIS7A;_8_XQl[P62JnDT]CmCbUj7h23|MSh9_eI6e]0CjT7d|8U[?bVV=)P3h5G[|P2PE5KcWP5h0R9n=M*hLSSH7_YT2KII)mPFc3F?J2kO4m9Q?FAoY)4l]B4BiP^m?2kAKo3S66WFI)b8V^ag)O6^JbJfMLfI=RlNjBc_jLRPSkieoe_^mlUYKUM[a)mNkJ`2e1*Y9f7;SNU`3cmW`ALTW3=AQG=aCeZW|m_1W]T|Ak`FP[V;:A(C_^ec|E1AH|64H)b9N9|Og)UXNm:;KU]9BKU9RaX[:O;8U]Pj(_9GGKTljhBBEih6]FM^[mY(f5?90a_gYQTF:Vjk(d6aXYFg?22O;nkac:c([=5*MWOYSB1Lk:C]CU?3OUbYE5[E`Rb9[dZmoM2cbMlNVb(L:7G4KlFJ)jRc;jY[BDR^KCRl7_DA4O9deA_kJelCI9MZZ5|MaG^;)6AHIIFA)DQYF1UIY2ZW9Bj?o1)c;4miI|O9?naLEBVJB_HooJ4hbN?]0|gU|*[?8TEBjn;nURLPjH=CT=1V]mnQQLgO)dYMGi9URZe[j1;FbCh7]Nog1EH0_EcUF7T=FK59Ra^dm9CO5lTNQK`j[YZ9Un9f98*W124H9C^coR[40KFRZCe;bV4leiRKF0;mD7TM]hZ)CKof50QGhJ95_AJ[o4]JG6?e9ECiI5FFa2f_AngCOc827ZUg]_EVi5A=]CPbFTE8^jNJdEXee*mKV6:kFZKF^?JojY4eA5]Q8M3bAG9k^l`FFRT=5ROdVhPGU8ieVfR;`_Ihga076jkOnCHO3;ZBWE9__kD33;^2IjJcacO*HbnhPCeikjGWn)_A=hB9fMEEFZC05Z:)a:Aaf1D3FYEYJ7]hLbI04(*N;`_TIFPWC4=H1KlF?JTNIVPDfaQ*SV)5D1h(Z^?5(A72O8cRc5X)OEc2m(DGjK8SaoQVCNaKhF:;J3bhA)i_LIl|(jcdP8H[7k=oY`_4j;BS6IdSSTNl3ZIV=COgTfRg0K9VjAQoD6WH]0)ESckYBHoS]fo_4nCLGBYU?aTkXB^P[N=C^dMoPCig;EI5`GD[7CgDgLF?lQf)[?)lja2BbDj[9ddi2fhnXYD8S3gU5cX84;?`TcK7)_glY)NMgdD;8|jT^(cbI6V7RQP0dA0[=MSYnN[VHmo7llEZNk]|V8`:NS`O7QVb=UamDkIhV)XhG^0m]^i]DXCUh^GJ2QQ;flaJ=^48boZfVjjg*HZGVV5Nlf=CL=J5E=MG;Ll8cAo1)abeC[5f?bkl(;agdI1g4h6Z`Id(AAkTU8Q[(fNoH;IfFf0*7X9ceh1E?i2(n)=Z^lCLbLMUTRlnHM0D53l*HmCa1ML^8mF5Ek7JGZM[ZaO0W7W:|j751[=_Z;OMI4EbS*7GflDRGJnc:`a^QYl=0NT=6UQO_|13Jl6CGL;H;eg;EmSkb0Leg(?55TUnSD*[J4:kC4GM484QEKl)nYFZfX79;HnJ4_AM1lLAndYJb2o5PXZ[EFKGcDW7COV`jmT?[fFHaAm*0=b_A46jBaA?HWGkTd)O:Cf?CBMkYWC^X|Ml9Whd=FbfUGlj_2Z0TnYG;Xc_Z:I=LbUn_1S8SjJ(m4Ec2?8G7m8237a]VS2Fe^9Whg|:oE(o^H=R0oQBCo_*dkW(_VC[C4=;:gk:;7mDThW|TRaG47DS;9O;ZU8F:0S8_Cl396UMZF[3O5FFDIFHJYjLHW^foNL3LB3?00Of373XTPEk60jm[iNbG|PgQC;^:anoh*|[n;R*aNZAC:gh?6PmRJ|jU]]|NSMojgRnn_;6FFNil*D_l|ERY`D2PimeG^bfBeJ7[L_dZMk]Zoe=9QbKCg9?M)kB?=HJdSoAhOnW3`*NMU)HgA7189n7S?T2Ne;Kog]OoEL;e(NlcCFbKZRo])7EnH_jAU|0)gfQFFmfTIZeU6jZOoK(OOCLZH7PMJoA0g3]bXn9)WnU2W[U?d)KI3=UQTgZo:E4(=Se8CEQ8koJ3)82T^FjY=1NI7TLd?O|oB5d_KHY=OHhT5ZFo70Tf0m1HZAn_N`Q:6_ZKdQJnoS?n6kGlR^M^X(akG3WgZmDn?0XESPG?okd1)KMBU8M0ch5BGRf|bmW7i(?^0)j)kPkn1lJ(i:C.mmf Question 14 Soit n un entier n a t u r e l . On d é f i n i t l ' e n t i e r A n = 1 + 5 n + 5 2 n + 5 3 n . A n ≡ 0 13 si est seulement si : □ n est un multiple de 5 □ n est un multiple de 4 □ n n ' e s t pas un multiple de 5 □ n n ' e s t pas un multiple de 4 MMF.7h|A6000gESKK]]64?d2oh?N8P6(|?N;gfA7MHeJDRXaBH6Z3fc:Y49UbI3XG6[XPo|GWEd^bN5531[TXHP5fg?KfITc|k=[[foW?bbF|dUl^iQO?5f|[iOCBKaH3VM9m^L|NKmi)gQif0oNK7J33gZ|AaO[n3JnV`ho0OEj^Uc1ZZ6(1RXJ492lV(CCXHT634B(D?Q9mBDgUdB0L_[;bk_9kG`h^SQM[5OC);jMgkPMEj_iI3HM_SZVQl4ZcK;=kSeH7k(QRFJcN7)O7W?W8:4]2J|T;9M`T2B3Vd)JoUEJR*jI[5KBG:9JgWGTnL4loCQHk^nCGJTadOGnlK21T45GBVdd)FbBKAE_A`[]76Pk2MZE1Ne:PkKcX)e4j?U(J7LZe4HgjBkmT5A*TmI)[:(PkFAHEc:|:aWFCXJeTf7WTf7MbK1F([aM6Mi)Q[)6j6mXBQIAUM(dXY4(LY16G)Hd1iZZX130V41;Yf31BP6S0jfA9h=GFk*J^PWfl(c3d=4dd1CA3=U`R9F(NLjh)5Q*b7;[1am6|ESS1LHc;9QI_9oKg1I(QL:3JfGH9M2lQ)C1mBiH1M[3D30:(`h7FXA?7A:ZH2b)SKTbQ4G*Q:09=4)A(Ek]b*CJQ[T02R)l?m(HBE?K4*?0(OXL0l0IPYUcU03g1*PKLHUmLe`3[_4RPgfk46C`8708PZ:d1*i1L6`V(9)7D;QC5EHR]4716ZBb5Bea119785d49]0LhB^5)cg5WS;_Pf:A`[FG;PHJJ8=XFm6:81ZO0LFZ:1GNGoWm2b|7*)QEYI0[E`1NE42IZUND[FQ=D6DdAKGE35UaA0|?Z`jLa)]MkZc*j2YjSK3G_P=3`(I];`X6Mj39bem`7:]`2iYJoHfZ0SD^P)M5n*d2`:3bFh9XF]UHU;kU5JaFX;jf4RTD2]5ZE2i[D;cFX[JVa)f^RnPYXGFFeJHEVP)Dh454d22PA=DFjAYW(5RDX2jTU=Ad5651oCbdYHYkH4]UOQa;5PM35FId92[6PO:lM5U3QN6VY8bRHLc`I6JX;BW3R?SAb4Y)eOcYlS9bW(4nd(VPOSZFS0_RN*TTAdNC`W`TUJ5_c_;^2=eIV]J:hfMTRJ(OTQEG8W8cN*WG98Ulf167gcVGknVde7=e;Gb2eSNAen?O=6Pi[391K|9?hjNNd`[`b8?6InUi7[CBBeZOX5DnRW=AjE:[_EKG]:Ig[Ne7h`]PnG^f(n[UHQ4?bAR)4aT[n:J)P2H3TG4E_7mG?NIcU]IImlkbCl6LiGF]Z6_M8g5b))`oiZak85i]M|WQLli[h)OYnbA;Lmh0_dbgBKKIkg:91LW[15kZ_fmC5^9alDfc]h5chDdoIHLTl0b]V0*IAk:[81=8MQeT4|UN19UZX:4K_:UWC6d3;U;GngLhP|*o`S4VoPV)*O7?kcXZC;IQlJo_4QJVjk0`dhJ5fCH|o[7MP(Fo]Q^`E(o]`3OjP3LJPL^6GSGd^Ph;=`eH^6g08TP;5T7K|0R6HA6l3X|*KER4K((RE1|FXA^`95_XMcM[XNI`iL:mkmiP)*)dm7*^Mi(Y)MC(QA?kHnX4`|fM8;EPO7fgQ7(igao^TndPCSmUHECU7cXVO]QM;nhFCC|hf?j[Ph1U|)SZ9nlLZ=F[fM31MS^?QlkMj|O5Vj_9J^ZD9nMm7ToW|O]7`(a=jm7Cn^YYOOe[5(7`RF3TSbELO]5_`ilOdj)_bWX50gCDID;5j7AVmFZobGYFmWUmk5)V^`cnf)ccW6B?Qg*k?Q_IX|om7onlfnaj8mlnnf88Tm4JX5MWTMf=CZOeb|W[J1[MSO:X`iQ[dfT|oMkj_nkm]NkH=oK7_Kl)aOUjOSGJgA4Bi`iN3fOmD*jQ_0knR7lgiXVeI0X(ccK9LM?GiLNn5SbVSm_d7]Z`cjK?oFD)IQ|D2GmAO]fQkHnhmdSO?fjccL(fkC^FOD[iGFDS_Wdf^fOmnC`TannXM_oSK??JWTi`3ol;B3l^J`.mmf Voir corrigé de QCM QCM corrigé Analyse numérique licence master QCM Analyse numérique licence master Q u ... 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